**Tricks to solve Percentage Problems**

Here we shall discuss about Tricks to solve Percentage Problems of the Quantitative aptitude section. Now a days this topic have become an important part of the Quant test in all Entrance Exams.So Here we will help you in this.We will provide short tricks on Percentage problems.

**Percentage is a fraction whose denominator is always 100. x percentage is represented by x%.**

**Percentage** word which is a combination of a word **” per cent “** that means for every hundred. The number, which is in a fraction form whose denominator is “100” is called as a percentage and the numerator of the same number is called as a rate per cent .

**How to calculate Percentage?**

**Percentage = ( Value / Total Value ) X 100**

**Percentage to Decimal Conversion or Fraction Conversion**

**1 = 100% **

**1/2 = 50% **

**1/3 = 33 1/3% **

**1/4 = 25% **

**1/5 = 20%**

**1/6 = 162/3%**

**1/7 = 142/7%**

**1/8 = 121/2%**

**1/9 = 111/3%**

**1/10 = 10%**

**1/11 = 91/11%**

**1/10 = 81/3%**

**1/13 = 79/13%**

**1/16 = 6.25%**

**5/4 = 125%**

**3/2 = 150%**

**2 = 200%**

**7/2 = 350%**

**To express x% as a fraction :**

We know, x% = x/100

Thus 10% = 10/100 (means 10 parts out of 100 parts) = 1/10 (means 1 part out of 10 parts)

**To express x/y as a percentage :**

We know that x/y = (x/y× 100 )

Thus 1/4 = ( 1/4 ×100 )% = 25% and 0.8 = ( 8/10 ×100 )% = 80%

**If the price of a commodity increases by R%, then reduction in consumption as not to increase the expenditure is = **[ R/(100+R)×100 ] %

**If the price of a commodity decreases by R%, then the increase in consumption as not to decrease the expenditure is** = [ R/(100-R)×100 ] %

**Let the population of a town be P now and suppose it increases at the rate of R% per annum, then**

Population after n years = P(1+R/100)^n

Population before n years =P/(1 + R/100)^n

**Let the present value of a machine be P. Suppose it depreciates at the rate of R% per annum.**

Value of the machine after n years= P(1-R/100)^n

Value of the machine n years ago=P/(1-R/100)^n

**For two successive changes of x% and y%, net change**= {x + y +xy/100}%