Tips & Tricks to Solve Alphabet Series Problems

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Tips & Tricks to Solve Alphabet Series Problems

Here in this article, we will discuss alphabetical series tricks.

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Two or three questions from alphabetic series is there in every exam. In such questions of alphabetic series, if the question consists of a single alphabet series, then you have to solve the logic implied in the sequence. Then fill in the missing character with a correct choice. Here in this article, we will discuss alphabetical series tricks.

Remember all the alphabets and their place number ,You can even note down during your exam.

A 1 26
B 2 25
C 3 24
D 4 23
E 5 22
F 6 21
G 7 20
H 8 19
I 9 18
J 10 17
K 11 16
L 12 15
M 13 14
N 14 13
O 15 12
P 16 11
Q 17 10
R 18 9
S 19 8
T 20 7
U 21 6
V 22 5
W 23 4
X 24 3
Y 25 2
Z 26 1

There are 26 letters in English alphabets.

The first half of alphabet series is from A to M and the half is from N to Z.

A-M – 1-13 (First Alphabetical Half)

N-Z –14-26 (Second Alphabetical Half)

So if you remember these intervals,It would be helpful in solving alphabet series problems.

 

Various types of Alphabetical series

Type – I: ALPHABET SERIES

Increasing by a definite number

For Example: IJKL? ( each letter increases by 1)

AGMSY? ( each letter increases by 6 place to its right position)

 

Decreasing by a definite number

For Example: ZXVTRP ? ( each letter decreases by 2 places to its left )

 

Increasing successively

 For Example: DEGJNS? ( +1,+2,+3,+4,+5)

 

Decreasing successively

For Example: ZYWTP ( -1,-2,-3,-4 ..)

ZTOKHFE ( -6,-5,-4,-3,-2,-1)

 

Decreasing and Increasing by a constant value.

For Example: DFCEBDACZ (+2,-3,+2,-3,…)

 

TYPE-II : ALPHANUMERIC SERIES

EX-1: Z1A, X2D,V6G,T21J,R88M, P445P,?

First letter: ZXVTRP (-2,-2,-2,…..)

Second letter: ADGJMP ( +3, +3,+3,…)

Series of numerals: 1,2,6,21,88,445 ( x1+1, x2+2, x3+3…)

So next term is N2676S.

 

EX-2: 2Z5,7Y7,14X9,23W11,34V13,?

First numeral- 2,7,14,23,34 (+5,+7,+9,+11..)

Second letter- ZYXWV ( decreases by 1 each time)

Third numeral- 5,7,9,11,13 ( increases by 2 each time)

 

EX-3 : W-144 , U-121, S-100, Q-81,?

First letter- decreases by 2 each time

Second numeral- square of 12,11,10,9,8..

 

TYPE-III : CONTINUOUS PATTERNS SERIES

Ex-1 : ab_ _ baa_ _ ab_

Options: i) aaaaa ii) aabaa iii) caabab iv) baabb

Solution: our answer is ii) . Here series aba is repeated

 

Ex-2 :ab_aa_bbb_aaa_bbba

Options: i) abba ii) baab iii) aabb iv) abab

Solution: our answer is ii) . The series is abb/aaabbb/aaaabbbb/a. Thus the letter are repeated twice , then thrice , then four times and so on .

 

Ex.3 – _bc_ca_aba_c_ca

Options i)abcbb ii)bbbcc iii)bacba iv)abbcc

Solution: our answer is i) . The series is abc/bca/cab/abc/bca. Thus the letter change in cyclic order .

 

Ex.4- _c_bd_cbcda_a_db_a

Options: i) adabcd ii) bdbcba iii) cdbbca iv)daabbc

Solutions: our answer is i). The series is acdb/dacb/cdab/acdb/da. Each group of four letters contains the letters of the previous group in the order – third , first , second and fourth.

 

Ex.5:- a_bb_baa_bbb_aa_

Options: i) aabba ii) bbaab iii)abaaa iv)baabb

Solutions: our answer is iii). The series is aabbbb/aaabbb/aaaa. At each step , the number of a’s increases by one while the number of b’s decrease by one.