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Directions (Q.1-5) : In the following questions, two equations are given. You have to solve both the equations and give answer.

1)
I. x2 +3x-28 = 0
II. y2 – y -20 = 0
a) x = y or relationship cannot be decided
b) x > y
c) x < y
d) x ≥ y
e) x ≤ y

2).
I.  5×2 + 11x+ 6 =0
II. y2 – 34y – 336 = 0
a) x > y
b) x ≤ y
c) x = y or relationship cannot be decided
d) x<y
e) x≥y

Answers to the quiz and More questions are attached in the Sehpaathi Test Application below

## Sehpaathi Test Application: CHALLENGE YOURSELF

3). I. 2×2+ 18x+ 40 = 0
II. 2y2 +15y+ 27 = 0
a) x<y
b) x≥y
c) x≤y
d) x > y
e) x = y or relationship cannot be decided

4). I.6×2-29x+35 = 0
II.3y2-11y+10=0
a) x ≥ y
b) x = y or relationship cannot be decided
c) x ≤ y
d) x>y
e) x<y

5). I. x2 + x – 20 = 0
II.y2 -y-30=0
a) x = y or relationship cannot be decided
b) x>y
c) x<y
d) x ≤ y
e) x ≥ y

1 – A

2 – C

3 – E

4 – D

5 – D

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