**Quadratic Equations Exercise Set-4**

Directions (Q.1-5) : In the following questions, two equations are given. You have to solve both the equations and give answer.

1)

I. x2 +3x-28 = 0

II. y2 – y -20 = 0

a) x = y or relationship cannot be decided

b) x > y

c) x < y

d) x ≥ y

e) x ≤ y

2).

I. 5×2 + 11x+ 6 =0

II. y2 – 34y – 336 = 0

a) x > y

b) x ≤ y

c) x = y or relationship cannot be decided

d) x<y

e) x≥y

**Answers to the quiz and More questions are attached in the Sehpaathi Test Application below**

**Sehpaathi Test Application: CHALLENGE YOURSELF**

**Test: Bnk_Reasoning_Quadratic-Equation_Set4**

3). I. 2×2+ 18x+ 40 = 0

II. 2y2 +15y+ 27 = 0

a) x<y

b) x≥y

c) x≤y

d) x > y

e) x = y or relationship cannot be decided

4). I.6×2-29x+35 = 0

II.3y2-11y+10=0

a) x ≥ y

b) x = y or relationship cannot be decided

c) x ≤ y

d) x>y

e) x<y

5). I. x2 + x – 20 = 0

II.y2 -y-30=0

a) x = y or relationship cannot be decided

b) x>y

c) x<y

d) x ≤ y

e) x ≥ y

Answers:

1 – A

2 – C

3 – E

4 – D

5 – D